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a) \(\frac{6}{5}.{\left( {1,2} \right)^8} = 1,2.{(1,2)^8} = {(1,2)^{1 + 8}} = {(1,2)^9}\)
b) \({\left( {\frac{{ - 4}}{9}} \right)^7}:\frac{{16}}{{81}} = {\left( {\frac{{ - 4}}{9}} \right)^7}:{\left( {\frac{{ - 4}}{9}} \right)^2} = {\left( {\frac{{ - 4}}{9}} \right)^{7 - 2}} = {\left( {\frac{{ - 4}}{9}} \right)^5}\)
a) \(3^3.3^4=3^{3+4}=3^7\)
b) \(5^2.5^7=5^{2+7}=5^9\)
c) \(7^5.7=7^{5+1}=7^6\)
a) `7^4 .7^5 .7^6 = 7^(4+5+6)=7^(15)`
b) `(54:3^7) .324 =( 2.3^3 : 3^7).2^2 x3^4`
`=(2: 3^4).3^4 .2^2`
`= 2.2^2=2^3`
c) `[(8+2^2).10^100] : (10^0 .10^94)`
`=(12 . 10^100) : 10^94`
`=12 . (10^100 : 10^94)`
`=12 . 10^6`
d) `a^9 :a^9 = a^(9-9)=a^0`
a)520 x 5 = 520 x 51 =5(20+1)=521
b)79 : 7 = 79 : 71 = 7(9-1) = 78
a) \(3^3 : 3^2\)=\(3^{3-2}=3^1\)
b) \(5^{4} : 5^{2}\)=\(5^{4-2}=5^2\)
c) \(8^{3} . 8^{2}\)=\(8^{3+2}=8^5\)
d) Cách 1:
\(5^{4} . 5^{3}: 5^{2}=5^{4+3}:5^2=5^7:5^2=5^{7-2}=5^5\)
Cách 2:
\(5^{4} . 5^{3}: 5^{2}=5^{4+3-2}=5^5\)
\(3^3.3^4=3^{3+4}=3^7\)
\(5^2.5^7=5^{2+7}=5^9\)
\(7^5.7=7^{5+1}=7^6\)
\(a,3^3.3^4=3^{3+4}=3^7\)
\(b,5^2.5^7=5^{2+7}=5^9\)
\(c,7^5.7=7^{5+1}=7^6\)
a) \(3^5.3^7=3^{5+7}=3^{12}\)
b) \(a^5.a=a^{5+1}=a^6\)
c) \(5^4:5^3=5^{4-3}=5^1=5\)
d) \(a^3:a^3=a^{3-3}=a^0=1\)
a, 7 2
b, a 4
c, 1
d, y 6